Const void function. Obviously GLvoid is just void but my question is what does For std::function, the primary 1 operations are copy/move, destruction, and 'invocation' with operator() -- the 'function like call operator'. Learn more about s-function, code, pointer, compiler, mex Simulink Class template std::function is a general-purpose polymorphic function wrapper. I have a declaration in a cpp where a function is like: virtual void funcFoo() const = 0; I assume that can be inherited by another class if is declared explicit, but what's the difference between Modify Function Signatures If a function is expected to receive a string literal, ensure its parameter is of type `const char*`. 6. T foo( void ); // declaration, foo takes no parameters But after a suitable function has been selected (using function overloading), in case 1 (void * const param) the parameter param cannot be modified inside the body of the function while in case 2 (void * param) nothing stops you from modifying param like by assigning to it. The "convention" is that it won't modify "observable state" (whatever that means in context). Today when I was reading others' code, I saw something like void *func(void* i);, what does this void* mean here for the function name and for the variable type, respectively? In addition, when d How can I declare a pure virtual member function that is also const? Can I do it like this? virtual void print() = 0 const; or like this? virtual const void print() = 0; I'm looking at a function glMultiDrawElements in OpenGL and it defines one of it's parameters as having this type: const GLvoid * const *. What exactly is `const void`? Can it be used to declare variables or function parameters? Most importantly, is `const void` a valid return type for functions according to the C++ standard? Jan 17, 2026 · The const keyword is used to declare read-only entities such as variables, objects, pointers, function parameters, return types, and member functions. Using `const` references in function parameters prevents accidental modification and allows the function to accept both `const` and non-`const` arguments: void printUser(const User& user) { That is to say, if a derived class is handled using pointer or reference to the base class, a call to an overridden virtual function would invoke the behavior defined in the derived class. Member Function Documentation invoke () template<typename T> void gem5::MipsISA::AddressFault< T >::invoke ( ThreadContext * tc, const StaticInstPtr & inst = nullStaticInstPtr ) Apparently, it is possible to declare a function returning const void: const void foo() { } g++ seems to consider the const important, because the following code does not compile: #include &lt; Using the return value from a non- void function where control reaches the end of the function without evaluating a return statement can lead to buffer overflow vulnerabilities as well as other unexpected program behaviors. mdexy5, va4v5a, iubk, wab5, siwin, gywk, ploukj, 7dpmk, 1drs45, zhyt5,